2x^2+2x=1.25

Solution for 2x^2+2x=1.25 equation:

2x^2+2x=1.25

We move all terms to the left:

2x^2+2x-(1.25)=0

We add all the numbers together, and all the variables

2x^2+2x-1.25=0

a = 2; b = 2; c = -1.25;
Δ = b2-4ac
Δ = 22-4·2·(-1.25)
Δ = 14
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{14}}{2*2}=\frac{-2-\sqrt{14}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{14}}{2*2}=\frac{-2+\sqrt{14}}{4}
$